Solution:
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 | #include<stdio.h> int main() { int T,N,K,i,P,D; scanf("%d",&T); for(i=1;i<=T;i++){ scanf("%d%d%d",&N,&K,&P); D = K+P; while(D>N) { D = D - N; } printf("Case %d: %d\n",i,D); } return 0; } |
Source Code: #include <stdio.h> int main () { char c; double a,b; printf( "Operation signs: \n\t For Addition \t\t : \t Press '+' \n\t For subtraction \t : \t Press '-' \n\t For multiplication \t : \t Press '*' \n\t For division \t\t : \t Press '/' \n\n Select an operation: \n " ); scanf( "%c" , & c); printf( "Enter a number: \n " ); scanf( "%lf" , & a); printf( "Enter another number: \n " ); scanf( "%lf" , & b); switch (c) { case '+' : printf( "%.1lf + %.1lf = %.1lf" ,a, b, a + b); break ; case '-' : printf( "%.1lf - %.1lf = %.1lf" ,a, b, a - b); break ; case '*' : printf( "%.1lf * %.1lf = %.1lf" ,a, b, a * b); break ; case '/' : printf( ...
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