Drafts of an Ordinary Programmer!

Solution: 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 #include<stdio.h> int main () { int T,N,K,i,P,D; scanf( "%d" , & T); for (i = 1 ;i <= T;i ++ ){ scanf( "%d%d%d" , & N, & K, & P); D = K + P; while (D > N) { D = D - N; } printf( "Case %d: %d \n " ,i,D); } return 0 ; }

Solution: 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 #include<stdio.h> #include<math.h> int main () { int a,b,i,s,sq; while (scanf( "%d%d" , & a, & b) && a != 0 && b != 0 ) { s = 0 ; for (i = a;i <= b;i ++ ) { sq = sqrt(i); if (i == sq * sq){ s ++ ; } } printf( "%d \n " ,s); } return 0 ; }

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